Function dbl [src]
Compute 2n (mod L)
Prototype
pub fn dbl(n: Scalar) Scalar Parameters
n: Scalar Source
pub fn dbl(n: Scalar) Scalar {
return Scalar{ .fe = n.fe.dbl() };
} pub fn dbl(n: Scalar) Scalar n: Scalar pub fn dbl(n: Scalar) Scalar {
return Scalar{ .fe = n.fe.dbl() };
}