Function sub [src]
Compute x-y (mod L)
Prototype
pub fn sub(x: Scalar, y: Scalar) Scalar Parameters
x: Scalary: Scalar Source
pub fn sub(x: Scalar, y: Scalar) Scalar {
return Scalar{ .fe = x.fe.sub(y.fe) };
} pub fn sub(x: Scalar, y: Scalar) Scalar x: Scalary: Scalar pub fn sub(x: Scalar, y: Scalar) Scalar {
return Scalar{ .fe = x.fe.sub(y.fe) };
}