Function formatNumber [src]

If the absolute value of integer is greater than or equal to pow(2, 64 * @sizeOf(usize) * 8), this function will fail to print the string, printing "(BigInt)" instead of a number. This is because the rendering algorithm requires reversing a string, which requires O(N) memory. See toString and toStringAlloc for a way to print big integers without failure.

Prototype

pub fn formatNumber(self: Const, w: *std.Io.Writer, number: std.fmt.Number) std.Io.Writer.Error!void

Parameters

self: Constw: *std.Io.Writernumber: std.fmt.Number

Source

  pub fn formatNumber(self: Const, w: *std.Io.Writer, number: std.fmt.Number) std.Io.Writer.Error!void {
    const available_len = 64;
    if (self.limbs.len > available_len)
        return w.writeAll("(BigInt)");

    var limbs: [calcToStringLimbsBufferLen(available_len, 10)]Limb = undefined;

    const biggest: Const = .{
        .limbs = &([1]Limb{comptime math.maxInt(Limb)} ** available_len),
        .positive = false,
    };
    var buf: [biggest.sizeInBaseUpperBound(2)]u8 = undefined;
    const base: u8 = number.mode.base() orelse @panic("TODO print big int in scientific form");
    const len = self.toString(&buf, base, number.case, &limbs);
    return w.writeAll(buf[0..len]);
}  