Function count [src]

Returns the number of needles inside the haystack needle.len must be > 0 does not count overlapping needles

Prototype

pub fn count(comptime T: type, haystack: []const T, needle: []const T) usize

Parameters

T: typehaystack: []const Tneedle: []const T

Example

 test count {
    try testing.expect(count(u8, "", "h") == 0);
    try testing.expect(count(u8, "h", "h") == 1);
    try testing.expect(count(u8, "hh", "h") == 2);
    try testing.expect(count(u8, "world!", "hello") == 0);
    try testing.expect(count(u8, "hello world!", "hello") == 1);
    try testing.expect(count(u8, "   abcabc   abc", "abc") == 3);
    try testing.expect(count(u8, "udexdcbvbruhasdrw", "bruh") == 1);
    try testing.expect(count(u8, "foo bar", "o bar") == 1);
    try testing.expect(count(u8, "foofoofoo", "foo") == 3);
    try testing.expect(count(u8, "fffffff", "ff") == 3);
    try testing.expect(count(u8, "owowowu", "owowu") == 1);
}

Source

  pub fn count(comptime T: type, haystack: []const T, needle: []const T) usize {
    assert(needle.len > 0);
    var i: usize = 0;
    var found: usize = 0;

    while (indexOfPos(T, haystack, i, needle)) |idx| {
        i = idx + needle.len;
        found += 1;
    }

    return found;
}  