Function deinterlace [src]

The contents of interlaced is evenly split between vec_count vectors that are returned as an array. They "take turns", receiving one element from interlaced at a time.

Prototype

 pub fn deinterlace( comptime vec_count: usize, interlaced: anytype, ) [vec_count]@Vector( vectorLength(@TypeOf(interlaced)) / vec_count, std.meta.Child(@TypeOf(interlaced)), )

Parameters

vec_count: usize

Source

  pub fn deinterlace(
    comptime vec_count: usize,
    interlaced: anytype,
) [vec_count]@Vector(
    vectorLength(@TypeOf(interlaced)) / vec_count,
    std.meta.Child(@TypeOf(interlaced)),
) {
    const vec_len = vectorLength(@TypeOf(interlaced)) / vec_count;
    const Child = std.meta.Child(@TypeOf(interlaced));

    var out: [vec_count]@Vector(vec_len, Child) = undefined;

    comptime var i: usize = 0; // for-loops don't work for this, apparently.
    inline while (i < out.len) : (i += 1) {
        const indices = comptime iota(i32, vec_len) * @as(@Vector(vec_len, i32), @splat(@intCast(vec_count))) + @as(@Vector(vec_len, i32), @splat(@intCast(i)));
        out[i] = @shuffle(Child, interlaced, undefined, indices);
    }

    return out;
}  