Function peek [src]

Look ahead at the next n codepoints without advancing the iterator. If fewer than n codepoints are available, then return the remainder of the string.

Prototype

pub fn peek(it: *Utf8Iterator, n: usize) []const u8

Parameters

it: *Utf8Iteratorn: usize

Source

  pub fn peek(it: *Utf8Iterator, n: usize) []const u8 {
    const original_i = it.i;
    defer it.i = original_i;

    var end_ix = original_i;
    var found: usize = 0;
    while (found < n) : (found += 1) {
        const next_codepoint = it.nextCodepointSlice() orelse return it.bytes[original_i..];
        end_ix += next_codepoint.len;
    }

    return it.bytes[original_i..end_ix];
}  